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SLIATE INTAKE FOR ACADEMIC YEAR 2018 (100% FREE FOR FULL TIME STUDENTS)   Applications are called for Higher National Diploma (HND) courses conducted by the Sri Lanka Institute of Advanced Technological Education (SLIATE) from those who have successfully completed the G.C.E Advanced Level Examination on or before 2017. HOW TO APPLY   All duly filled applications prepared according to the specimen application form appearing below should be sent to the relevant Advanced Technological Institute (ATI)/ATI Section as mentioned in section “B”, under registered cover with the bank receipt obtained by crediting Rs.500/= (Five hundred rupees) to the SLIATE account No. 025-2-001-1-3397613 at Peoples’ Bank, Hyde Park Branch Colombo 02 or any other branch of the Peoples’ Bank in Sri Lanka. The course applied for should be clearly stated at the top left-hand corner of the envelope. Candidates who wish to apply for more than one institute should submit separat...

Advance Level Chemistry Full Tamil Notes... Chemical Bonds Part 1 Download Chemical Bonds Part 2 Download General Chemistry Download Inorganic Part 1 Download Inorganic Part 2 Download Inorganic Part 3 Download Organic Part 1 Download Organic Part 2 Download Organic Shot Notes Download Physical Chemistry Part 1 Download Physical Chemistry Part 2 Download Physical Chemistry Part 3 Download Thermal Dynamics Download Get paid to share your links! Get paid to share your links!

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Ionic Equilibrium Past Papers Collection MCQ and Structured Question 1983 - 2014 Download Ionic Equilibrium H 2 O is the medium of biological systems one must consider the role of this molecule in the dissociation of ions from biological molecules. Water is essentially a neutral molecule but will ionize to a small degree. This can be described by a simple equilibrium equation:  H 2 O ↔ H + + OH –   This equilibrium can be calculated as for any reaction: Since the concentration of H 2 O is very high (55.5M) relative to that of the [H + ] and [OH – ], consideration of it is generally removed from the equation by multiplying both sides by 55.5 yielding a new term, K w : K w = [H + ][OH – ] This term is referred to as the ion product. In pure water, to which no acids or bases have been added: K w = 1 x 10 –14 M 2 As K w is constant, if one considers the case of pure water to which no acids or bases have been added: [H + ] = [OH - ] = 1 x...